Geometry, June 2015, Questions 26
26. The diagram below shows parallelogram LMNO with diagonal LN, m<M = 118o, and m<LNO = 22o.
Explain why m<NLO is 40 degrees.
The opposite angles of a parallelogram are congruent. Therefore, m<O = 118o.
Triangle LNO has 180 degrees, so m<NLO + m<LON + m<LNO = 180
m<NLO + 118 + 22 = 180
m<NLO + 140 = 180
m<NLO = 40 degrees.
Any questions?
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