Wednesday, March 22, 2017

Algebra 2 Regents Problems of the Day

The following problems were taken from the ALGEBRA II (Common Core) Regents Exam given on Friday, January 27, 2017.
Previous problems can be found here

Part 1

3. When factored completely, m5 + m3 - 6m is equivalent to

(4) m(m2 + 3)(m2 - 2)
Start with: m5 + m3 - 6m
Each term has m, factor it: (m)(m4 + m2 - 6)
Factor into two binomials: What are two factors of -6 that add up to +1: +3 and -2
So it factors into m(m2 + 3)(m2 - 2).

4. If sin2(32°) + cos2(M) = 1, then M equals

(1) 32°.
The rule is: sin2x + cos2x = 1.
In this case x = 32°, so M must be 32° as well.




Continue to the next problems

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