Previous problems can be found here
Part 1
3. When factored completely, m5 + m3 - 6m is equivalent to
(4) m(m2 + 3)(m2 - 2)
Start with: m5 + m3 - 6m
Each term has m, factor it: (m)(m4 + m2 - 6)
Factor into two binomials: What are two factors of -6 that add up to +1: +3 and -2
So it factors into m(m2 + 3)(m2 - 2).
4. If sin2(32°) + cos2(M) = 1, then M equals
(1) 32°.
The rule is: sin2x + cos2x = 1.
In this case x = 32°, so M must be 32° as well.
Continue to the next problems
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