## Thursday, June 18, 2015

### Math Regents Questions

Until I get a chance to type up the Regents questions, if anyone has a specific question about a specific problem, leave it in the comments and I'll get to it as soon as possible.

Be sure I know which test you're talking about. There were TWO Algebra exams.

Anonymous said...

looking for solution for final question

(x, why?) said...

Which exam? Today's integrated Algebra on yesterday's Common Core Algebra exam?

Anonymous said...

Common Core

Holly said...

Very last question Algebra I?

(x, why?) said...

Common Core, question 37, football question.
I can't post images in the comments, but I can refer you to http://www.wolframalpha.com
Just cut and paste the text into the input box.

To get the graph, enter the equation into your graphing calculator and look at the table of values. You have 30 boxes across, so count by 5. You need to go as high as 25, so count by 2 on the y-axis. (Counting by 5 on the y-axis is probably too much and will shrink the graph.)

graph f(x)=-1/225(x)^2+2/3(x), when 0<x<150

will show you the graph, with zeroes at 0 and 150.

vertex f(x)=-1/225(x)^2+2/3(x)

will show you that the vertex is at (75, 25), which is in your table of values.

Finally, multiply 45 yards by 3 to get 135 feet. Put 135 into the original equation (or look it up on the graph or on your table of values.

y =-1/225(x)^2+2/3(x), x = 135

x = 135, y = 9, which is under the bar, which is at 10 feet.

(x, why?) said...

I have to wait until all papers are collected before I can get a copy of today's exam. Extended time just finished a few minutes ago, so I hope to get one soon.

If I remember correctly, it was an inequality question about pay phones.

It was something like .10(m - 4) + .25 <= the amount of money the guy had.

The (m - 4) is necessary because the .25 covered the first 4 minutes.
Distribute and solve for m.
Make sure you use the largest integer value (no decimals).

Anonymous said...

Thank You
I was unable to graph the parabola
My ti84 graphed a diagonal line. I tried multiple resets to calculator default to no avail.
http://www.wolframalpha.com graphs it correct but I still cannot graph on my tI84

Holly said...

Im sorry can you provide #36? Thank you for the best blog on the net!

Holly said...

Anonymous - have you updated your ti84 recently?

Holly said...

#36 Algebra I, sorry did not indicate test.

Anonymous said...

Yes TI-84 Plus ver 2.55
up to date

(x, why?) said...

Anonymous,

Getting a diagonal line is strange. Usually it means that you don't have the exponent entered correctly, and it's interpreting it as a linear function. Have you tried entering it as I wrote it for the wolframalpha site to see if it worked that way?

(x, why?) said...

Exponential regression, which can be done in the calculator.
Off the top of my head since I don't have one handy, it increases by 60, 90, 135 ... which increasing by half.

so an equation could be y = 120(1.5)^(w-1)

Using that formula, on the 26th week, there would be 3030140 downloads (rounded)

Using that formula, on the 52nd week, there would be 1.15 X 10^11 downloads, which is not a reasonable number because it is more than the number of people on the planet to begin with, all of whom, by this point, would have already downloaded it.

I'm curious if anyone is going to explain that apps die out after a few months and wouldn't keep growing.

Anonymous said...

Could you provide an answer and an explanation for question number 24 on the Common Core Algebra test.

Thanks

M said...

Hi... new to your blog. My students are FREAKING out about the CC exam but for some reason I won't get a copy from my dept head until next week and I'm dying to check it out. Any idea when you'll have the questions up? No rush, just wondering. Thanks for doing this.

(x, why?) said...

M,

I typed up about half the questions (no images), so hopefully later tonight. Taking a little extra time because of the number of goof-ups in the CC Geometry test a couple weeks ago.

(x, why?) said...

Anonymous,

Question 24 -- I'll post the explanation later this evening -- it's long to work out and I'd rather use a graphic, but the answer is (4) 750 < p < 1500

Short version: put this in your calculator y = (2.25x + 750)/x
Check the Table of Values for when the value of y drops to 3.25 -- it won't happen until 750. (And if you have the patience, it drops to 2.75 at 1500.)

M said...

Thanks! Ill be able to sleep tonight if I can check out the questions. Only one student said it was easy. Usually I have quite a few.

Anonymous said...

how about question 28 - seemed to be a lot of debate around that one after the test!!

(x, why?) said...

The multiple choice is online at
http://mrburkemath.blogspot.com/2015/06/new-york-state-algebra-i-common-core.html

And now I'm having dinner and watching Jeopardy.
Back later.

Anonymous said...

Okay, so there was one question about weekly earning and salary. I thought that because the question said salary and didn't specify weekly or yearly, so I assumed yearly. I ended up with a difference of \$10400 in salary. Was this the correct answer or was it weekly (\$200)? I don't remember the question number and I can't seem to figure this out. Any insight would be appreciated.

Anonymous said...

I am the author of the above post and I was talking about the Algebra I exam. (just to make sure)

(x, why?) said...

Okay, Question 28 for Anonymous -- really, it'd be easily more of you had names.

The subtraction gives you 2x^2 - 5x + 7. Times 1/2x^2 gives x^4 - 2.5x^3 + 3.5x^2.

(x, why?) said...

Q34: The salary question. This is how overtime generally works in the real world.

They were specifically asking about one person working 52 hours and the other working 38. That's just for one week. (People don't always work the same number of hours every week.)

The 38 hour employee earned \$380. (38 * 10)
The 52 hour employee earned \$400 + 12 * 15 = \$580. The difference is \$200.

In order to earn \$445, they need to work 40 hours, earning \$400, and then another \$45, which at \$15/hour is three more hours, for a total of 43 hours.

Anonymous said...

Thanks for the answer on qestion 34. The wording really confused me. I shouldn't have changed my answer.

Anonymous said...

I forgot what number it was, but what was the answer to the question regarding agreeing or disagreeing with Albert? If you showed your work, but ended up getting the wrong answer, do you still get partial credit?

Anonymous said...

Whoops, forgot to mention that the Albert Question was on the Algebra CC.

Anonymous said...

Anonymous said...

Looking for part two first short answer .algebra 1

(x, why?) said...

Part 2, Q 25, the absolute value graph.

Basically, a V shaped graph with a vertex at (3, 0).

If has changed from y = |x| in that the graph is shifted three units to the right.

Anonymous said...

Thank You
I was unable to graph the parabola
My ti84 graphed a diagonal line. I tried multiple resets to calculator default to no avail.

Why i got the diagonal line. I entered -1/225x^2+2/3x

omitted multiplying by x
-1/225(x)^2+2/3(x)

I was running out of time and just free-handed a parabola- rushed thru and missed ft/yard conversion so it went over the bar.

Anonymous said...

Last night, I asked about the Albert Question, and I put yes because I had gotten x= -0.75 and y =6 for both of them. However, I think I solved the second system of equations wrong. Did they both have the same x and y value?

Anonymous said...

This post is for "Anonymous"....

The reason you weren't able to see the parabola in question 37 is because the turning point wasn't until x=75, so the picture of the solution appears to be linear. If you zoom out, you can see the curve.

Not going to lie....struggled with it myself for a while!

(x, why?) said...

1. Albert: I don't have my notes with me, but I remember that they had the same solution. Yours looks right, from what I remember.

2. THANK YOU! About the calculator. It hadn't occured to me (since I don't have one in front of me) that the window needed to be adjusted to see the entire thing, and if not, then yes, it would look like a bid diagonal line.

Something like that happened with me some time back when I was making a comic on my blog called The Superman Function. I kept getting what looked like a bunch of vertical lines. I needed to zoom out to see the big picture.

Anonymous said...

Anonymous said...

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Anonymous said...

can u post the geo regents answers integrated

Anonymous said...

Regarding the computer and printer inequality graph, I was extremely confused. I would like an explanation and help on that, too, please. I only had ten minutes left and I still had to finish Part IV, so I didn't really have much time to think about that question. I tried thinking of the computers and printers in terms of x and y but that didn't work out. In addition, for Part IV, how many points would you get out of the six if you only got the last part of the question wrong (Would the football be able to reach the post that's ten feet high)?

(x, why?) said...

Unfortunately the Geo test was still happening when I left work to report to my grading assignment, so I wasn't allowed to take a copy with me. I won't see it until Monday. (I'm also working overtime this weekend grading -- even Fathers Day, so I don't know when I could've gotten to it anyway.)

If you can give me the info about a question, I can try to help with it.

(x, why?) said...

Ditto for the Alg 2/trig test. I don't have a copy of it, and I don't usually post those, except for the questions that my Alg 1 students should be able to answer.

Anonymous said...

On the geometry regular regents, there was a question on the plane. I think it asked what plane is perpendicular to ad ? Please take a look at that question!! It was question 22 I believe.

Anonymous said...

Please post regular integrated geometry regents answers when you get a chance ,,
Thanks!

(x, why?) said...

Part 2 is posted: http://mrburkemath.blogspot.com/2015/06/new-york-state-algebra-i-common-core_20.html

Reminder: Geometry can't be posted before Monday, because I have the exam.

Algebra 2 is not going to be posted. Sorry.

Integrated Algebra may be posted, if there's any interest, after Geometry.

Anonymous said...

geometry regents plz put up sir

Anonymous said...

can you also put up the global hisotory regents p,lz sir

derrick said...

please put up the normal geometry regents thanks

Anonymous said...

Hi,
Your step by step instructions have been extremely useful considering I didn't pass the algebra common core regents in June. So having it be explained made things so clear and it has really helped me study so I wanted to say thank you. I have a question about question number 35 of part 3. I have no idea on how to even begin to graph/ answer the question.

(x, why?) said...

To graph a line in Standard form without rewriting it in slope-intercept form, follow these steps:

First, find the x-intercept (or in this question, c) by choosing the value of 0 for y (in this question, it's p). Solve for x.

Then do the same thing to find the y-intercept. Use 0 for the x value and solve for y.

Plot those points and draw the line.

If those points aren't whole numbers, try to find a pair of numbers that will work. You need at least two points to draw the line (or to find the slope of the line so that you can locate more points).

If the graph is an inequality, shade the correct side of the line. I hope this helps.