When is a **Parallelogram** not also a **Rhombus**? That's not a riddle, although if I think of a good punchline for it, I could make a comic out of it.

No, this is a serious **Geometry** question. In fact, it was the proof on the **June 2014 Geometry Regents** exam.
Specifically, question 38 read as follows:

*The vertices of quadrilateral JKLM have coordinates J(-3,1), K(1,–5), L(7,-2), and M(3,4).
*

Prove that JKLM is a parallelogram.

Prove that JKLM is not a rhombus.
**EDIT: ***Co-ordinates fixed.*
**EDIT: Link added -- ***June 2014 Geometry Regents, question 38.*
Additionally, a grid was provided, but its use was optional. What

*wasn't* given was enough space to write the answer, unless you thought to flip to the following page. The good news was that you did NOT have to write a two-column proof, but you did have to show your work and give the details.

This is a question my students should be able to answer easily. They probably didn't, but they should have. There are reasons why I say this.

When I approach any question that contains the word *"Prove"*, I try to get the students to think of any TV show courtroom drama they've ever scene. (Sit-coms are a totally different animal, here.) Few of them might know what it's like to be in a real courtroom, so I settle for the simplified version. Each side will give an opening statement, and they will state what they are setting out to prove. They were present their evidence and build a case out of all the evidence they bring forward. There isn't one magic witness or exhibit that will hand-wave the case away. (If there were, the case likely would never have been brought.) Then, in the end, there are summaries, which include the lawyers' conclusions based on the evidence that they've presented, and they implore the jury to reach the same conclusion.

Students are different. Students, who a year earlier in **Algebra** would have me solve a five-step problem in 17 steps, and repeat the solution and check twice because they still weren't "getting it", will look at a **Geometry** "proof" and say, "It's true because, you know, **Math**."

They're not sure what the "Math" is, but the Math is there, so it must be true.

The point is that they *need* to be sure.

This led to some interesting discussions online about the test question. How do you know, for example, if you gave enough information for only 2 points and not for 4 points?

Let's get to the basics

### Parallelograms and Rhombuses

*Prove that JKLM is a parallelogram. Prove that JKLM is not a rhombus.*
How do you prove that a quadrilateral is also a parallelogram?

You have several choices: if the opposite sides are parallel, or if the opposite sides are congruent, or if the diagonals bisect each other, then the figure is a parallelogram.

This statement, whichever one or ones you use, has to be your conclusion, but you have to back those up with evidence:

- To prove opposite sides are parallel, you need to find the slopes of the four sides
- To prove that the opposite sides are congruent, you need to find the lengths of the four sides
- To prove that the diagonals bisect each other, you have to find the midpoints of both diagonals.

Any of those are easy to do, although I'd say that slopes and midpoints are quicker to find than the lengths. Which one you do is up to you, but you can save time if you keep the second part of the question in mind. Using the slopes for the parallelogram is fine, but it won't help you with the rhombus.

That being said, I'd probably find the slopes first **just because** it's pretty much second-nature to me to do that first.

How do you prove that a quadrilateral is rhombus?

You have a couple of choices: if all four sides are congruent, or if the diagonals perpendicularly bisect each other, then the figure is a rhombus.

This statement, whichever one or ones you use, has to be your conclusion, but you have to back those up with evidence:

- To prove that the opposite sides are congruent, you need to find the lengths of, at least, two consecutive sides. If you know it's a parallelogram, then you know that the opposite sides are congruent. It would've helped if you did the distance formula before now, instead of slopes, but you aren't penalized for doing extra work.
- To prove that the diagonals perpendicularly bisect each other, you have to find the slopes of the diagonals. If you know it's a parallelogram, then you know that the diagonals bisect each other. You don't need to prove this, even if you didn't show it earlier.

**So how much work is actually required for this problem?**

Believe it or not, you could have solved this problem simply by finding the lengths of the four sides. Is that worth 6 points? No, that was worth *2 points*. The rest of the points came from you conclusions and your reasons. Just because you found the lengths, you haven't (and this isn't meant to be a plotting reference) *you haven't connected the dots yet*. You haven't given a conclusion, nor stated under what rules this proves your case.

*JKLM is a parallelogram because the opposite sides are congruent. *(Work is shown for this.) *JKLM is NOT a rhombus because all four sides are NOT congruent.*

or

*JKLM is a parallelogram because the diagonals bisect each other.* (Work is shown for this.) *JKLM is NOT a rhombus because the diagonals are not perpendicular.* (Work is shown for this.)

Either of these would be complete answers good for full credit.

By contrast "They're parallel." ... well, just isn't.

As you can see, the slopes of the sides aren't needed for the problem, but it isn't incorrect to find them. Other work left for the reader: find the lengths of the sides, and the midpoints and slopes of the diagonals.