More Algebra 2 problems.
January 2018
11. If n = sqrt(a5) and m = a, where a > 0, an expression n/m could be
(1) a5/2
(2) a4
(3) (a2)1/3
(4) (a3)1/2
See image below
Answer: (4) (a3)1/2
The square root of a value is the same as raising it to a power of 1/2, so n can be expressed as a5/2.
Also, m can be expressed as a1.
This means that n/m is the same as (a5/2)/a1.
When dividing, keep the base, subtract the exponents: a(5/2 - 1) = a(3/2)
A fractional exponent of 3/2 would mean take the square root of the third power, which is choice (4).
12. The solutions to x + 3 - (4 / (x - 1) ) = 5 are
Answer: (1) 3/2 + sqrt(17)/2
Follow the logic in the image:
Subtract 5 from each side, then add (4 / (x - 1)) to each side.
This will set up a rational equation. Multiply both sides by (x - 1) -- or "cross-multiply", if you prefer.
Multiply the binomials, then set up the quadratic equation to solve.
Use the Quadratic Formula to find the roots. Note that you have a positive discriminant, so the roots are real, and there is no "i" in the answer.
If you split the file fraction, you get choice (1).
Comments and questions welcome.
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