Geometry Problems of the Day (Geometry Regents, June 2025 Part III)

This exam was adminstered in June 2025.

June 2025 Geometry, Part III

Each correct answer is worth up to 4 credits. Partial credit can be given. Work must be shown or explained.

32. A store sells colored craft sand with a base length of 4 inches and a height of 7.5 inches.

Container 1: A square prism with a base length of 4 inches and a height of 7.5 inches.

Container 2: A cylinder with a diamter of 5 inches and a height of 6 inches.

Container 3: A cone with a diamter of 7.5 inches and a height of 8.5 inches.

If the containers are filled to the top, which container will hold the most sand? Justify your answer.

Answer:

Find the volume of all three containers and answer the question.

V₁ = (4)(4)(7.5) = 120

V₂ = (2.5)²(6)π = 117.8097...

V₃ = 1/3 π (3.75)²(8.5) = 125.1728...

Container 3 holds the most sand.

33. Quadrilateral MIKE has vertices with coordinates M(-1,-3), I(-3,3), K(5,4), and E(7,-2).

Prove MIKE is a parallelogram, and prove MIKE is not a rhombus.

[The use of the set of axes below is optional.]

Answer:

You don't have to graph the figure but it will make the problem easier to visualize. Parallelograms have opposite sides parallel. Or they have opposite sides congruent. Rhombus has four congruent sides. Or Rhombuses have diagonals with perpendicular slopes.

The "OR" clauses above are there to say that there are multiple ways to solve this problem, but you must show the work and state your conclusions.

THe "easiest" way to do this is to finding the slopes of the sides and the diagonals. If you graph the image, you can simply count boxes without using any formulas.

The slope of MI = -6/2 = -3. The slope of IK = 1/8. The slope of KE = -6/2 = -3. The slope of EM = 1/8.

The opposite sides have the same slope, so MI || KE and IK || EM. The opposite sides are parallel, so MIKE is a parallelogram.

The slope of MK = 7/6. The slop of IE = -5/10 = -1/2. The product of (7/6)(-1/2) =/= -1, so the diagonals are not perpendicular. Therefore, MIKE is not a rhombus.

--- OR ---

The length of MI = √(4 + 36) = √(40). The length of IK = √(64 + 1) = √(65). The length of KE = √(4 + 36) = √(40). The length of EM = √(64 + 1) = √(65).

The opposite sides of MIKE are congruent. Two pairs of congruent sides means the quadrilateral is a parallelogram.

The consecutive sides of MIKE are NOT congruent. Therefore, MIKE is not a rhombus.

You can mix and match. For example, use the slopes to show that it is a parallelogram and then use the lengths of MI and IK to show it is not a rhombus.

Make sure all concluding statments are written.

34. A park ranger needs to secure two different trees with wire. A wire is to be attached from a stake in the ground to each tree. The wire is attached at two different heights and two different angles of elevation, as indicated in the model below.

The park ranger has 20 feet of wire. Does the park ranger have enough wire to secure both trees? Justify your answer.

Answer:

A "yes" or "no" answer without any justification is worth zero points. Also, forgetting to say "yes" or "no" will cost you a point.

You have the opposite sides of two right triangles and you are looking for the lengths of both hypotenuses. You need to use SINE twice.

If you use Cosine or Tangent, that is a conceptual error and you will lose half credit.

sin (24) = 4 / w₁
w₁ = 4 / sin (24) = 9.83...

sin (11.6) = 3 / w₂
w₂ = 3 / sin (11.6) = 14.92...

Since 14.92 + 9.83 24.75, which is more than 20 feet, NO, the ranger will not have enough rope.

End of Part III

How did you do?

Questions, comments and corrections welcome.

I also write Fiction! The NEW COLLECTION IS AVIALABLE! A Bucket Full of Moonlight, written by Christopher J. Burke, contains 30+ pieces of short stories and flash fiction. It's available from eSpec Books! Order the softcover or ebook at Amazon. Vampires, werewolves, angels, demons, used-car salesmen, fairies, superheroes, space and time travel, and little gray aliens talking to rock creatures and living plants.
My other books include my Burke's Lore Briefs series and In A Flash 2020.
If you enjoy my books, please consider leaving a rating or review on Amazon or on Good Reads. Thank you!

Geometry Problems of the Day (Geometry Regents, January 2025 Part III)

This exam was adminstered in January 2025.

January 2025 Geometry, Part III

Each correct answer is worth up to 4 credits. Partial credit can be given. Work must be shown or explained.

32. Modeled by right triangles below, a surveyor (S) is taking land measurements using a cabin (C), a boulder (B), and a tree (T) as fixed points of reference. The cabin, boulder, and tree are collinear. The surveyor is 917 meters from the cabin, 1048 meters from the boulder, and 1425 meters from the tree.

Determine and state, to the nearest degree, the measure of ∠BST.

Answer:

CST is a right triangle. CSB is also a right triangle. BST is not a right triangle, so you can't you one trig function. However, you can use TWO trig functions. If you find the measure of ∠CST and then subtract the measure of ∠CSB, the difference will be the measure of ∠BST. In each case, we have the adjacent side (917) and the hypotenuse (1425 and 1048), so we need to use cosine two times.

cosine x = 917/1425
x = cos^-1(917/1425) = 49.946 degrees

cosine y = 917/1048
y = cos^-1(917/1048) = 28.955 degrees

Subtract 49.946 - 28.955 = 20.991. So the measure of ∠BST is 21 degrees to the nearest degree.

33. A garden bed, pictured below, is a square prism with a rectangular prism taken out. The inside length of the square prism is 6 feet. The rectangular prism taken out has a width of 2 feet and a length of 4 feet.

The diagram below shows the top view of the garden bed with its inside measurements.

The garden bed is filled with topsoil to a uniform height of 1.25 feet.

Determine and state the volume of the topsoil, in cubic feet.

Each bag of topsoil sells for $3.68 and contains 2 cubic feet of topsoil.

Determine and state the total cost of the bags of topsoil that must be purchased to fill the garden.

Answer:

TO find the area of the U-shaped garden bed, either break it into three rectangles and find each area separately, OR draw a line on the bottom to create a square, find the area of the square and subtract the rectangle in the middle.

Whichever way you do it, the area of the base is 28 square feet.

The Volume is the Area of the Base times the height, so 28 * 1.25 = 35 ft³.

If each bag of topsoil contains 2 cubic feet of topsoil, then you need 35/2 = 17.5 or 18 bags. You need to ROUND UP to the next integer. You have to buy a Whole Number of bags and if you round down, you will not have enough topsoil to finish the job.

If you buy 18 bags at $3.68 each then (18)(3.68) = $66.24

34. Given: △ACD with ABC, AED, and BE || CD

Prove: AB • AD = AE • AC

Answer:

This seems like an odd thing to prove. Why do you care if these products are equal? But if you divide both sides of this equation by AC and AD, we get a proportion of corresponding sides of the triangles. So we need to first show that these triangles are similar, so that we can prove something about the cross products.

Statement	Reason
1.BE || CD	Given
2. ∠ABE ≅ ∠ACD	Alternate interior angles of parallel lines are congruents
3. ∠AEB ≅ ∠ADC	Alternate interior angles of parallel lines are congruents
4. △ABE ~ △ACD	AA Theorem
5.AB / AC = AE / AD	Corresponding sides of similar traingles are proportional.
6. AB • AD = AE • AC	The product of the means equals the product of the extremes.

You could also have stated that "Cross products are equal." However, "cross multiply" was NOT acceptable. The best that I could figure is that the former is a reason while the latter is a command.

Also, you could have used that ∠A ≅ ∠A by the Reflexive Property in place of Step 2 or Step 3.

End of Part III

How did you do?

Questions, comments and corrections welcome.

I also write Fiction! The NEW COLLECTION IS AVIALABLE! A Bucket Full of Moonlight, written by Christopher J. Burke, contains 30+ pieces of short stories and flash fiction. It's available from eSpec Books! Order the softcover or ebook at Amazon. Vampires, werewolves, angels, demons, used-car salesmen, fairies, superheroes, space and time travel, and little gray aliens talking to rock creatures and living plants.
My other books include my Burke's Lore Briefs series and In A Flash 2020.
If you enjoy my books, please consider leaving a rating or review on Amazon or on Good Reads. Thank you!

Geometry Problems of the Day (Geometry Regents, June 2025 Part II)

This exam was adminstered in June 2025.

June 2025 Geometry, Part II

Each correct answer is worth up to 2 credits. Partial credit can be given. Work must be shown or explained.

25. In the year 2020, the village of Depew, New York had an area of 5.1 square miles and a population of 15,069. In the same year, the village of Lancaster, New York had an area 2.7 square miles and a population of 10,087.

Which village had the larger populatio density in 2020? Justify your answer.

Answer:

Density is mass divided by volume, but population density is population divided by square footage. Find the density of both cities.

The population density of Depew is 15069/5.1 or about 2954.7.

The population density of Lancaster is 10087/2.7 or about 3735.9.

Lancaster had the larger population density.

You only got both credits if you answered the question and showed work. An answer of "Lancaster" without any work is woth 0 points.

26. In △ABC below, AC is extended through C to D, m∠A = (3x - 22)^o, m∠A = (4x - 18)^o, and m∠BCD = (6x - 23)^o.

Determine and state m∠ACB.

Answer:

This is a two-part problem and, if you ask me (and no one did), a little too involved for a 2-point question.

The exterior angle is equal to the sum of the two remote angles. You need to write an equation to solve for x. Then you have to find the size of angle BCD. AND THEN you have to find the measure of the angle supplementary to the exterior angle.

Again, a little much.

3x - 22 + 4x - 18 = 6x - 23
7x - 40 = 6x - 23
x = 17

This means that the exterior angle is 6(17) - 23 = 79. So angle ACB = 180 - 79 = 101 degrees.

27. Parallelogram ABCD is shown below. Using a compass and straightedge, construct the altitude from point A to side DC. [Leave all construction marks.]

Answer:

From point A, draw an arc the length of AD. OR extend line CD and draw an arc of any length that intersects CD in two places.

From the two points of line CD, make arcs below CD. Make a point where the two arcs intersect. Call it anything, say E. with a straightedge, draw AE.

That's it.

If you made the altitude from points B, C, or D, you only got one point. If you did it from any other point, or if you made a perpendicular bisector of CD, you score no points.

28. Quadrilateral QUAD is graphed on the set of axes below.

Determine and state the area of quadrilateral QUAD.

Answer:

It was quite easy to show that the diagonals of the quadrilater were perpendicular to each other because the diagonals were vertical and horizontal lines. However, the question did not say that this was a parallelogram. It only said it was a quadrilateral.

It is also easy to see that QUAD could be broken up into four congruent triangles, for which the area could be found.

HOWEVER, this past January, there was a similar question where the figure was NOT so nice. As a result, the easiest way to find the area was to draw a rectangle box around the figure, find the area of individual triangles between the shape and the rectangle, and then subtract. What remained was the area of the figure. That wasn't necessary to do her, BUT anyone who practiced that exam in the days before this exam would've been more likely to take this approach.

I will say that I saw a few answers based on the fact that it is a rhombus. To use those formulas, however, you needed to show that it was a rhombus. This was a lot of extra work for 2 points, but more power to whoever did it this way!

If you draw the two diagonals, you will split QUAD into four triangles. Each of those triangles has a base of 5 and a height of 3.

So Area = 4 (1/2) (3) (5) = 30

If you found the area of the rectangle around QUAD, it had a length of 10 and a width of 6, for an Area of 60. If you then subtracted the four triangles, each of which was 5 by 3, you got 60 - 30 = 30.

Common mistakes were finding the perimter, or finding the lengths of the sides and then sqauring it, assuming that the shape was a square.

29. In a right triangle, the acute angles have the relationship sin(3x - 7)^o = cos(x + 1)^o

Determine and state the value of x.

Answer:
If the sine value is equalt to the cosine value than the sum of the two angles must be 90 degrees. (The "co" is "cosine" means "complementary", and complementray angles add up to 90 degrees.

3x + 7 + x + 1 = 90
4x - 6 = 90
4x = 96
x = 24

Common mistakes are to set the two expressions equal to each other, which is a conceptual error, setting the sum equal to 180, another conceptual error, or any computational mistakes solving the algebraic equation.

One mistake costs one point. Two points results in a score of zero.

30. In circle A below, m∠BAM = 36°

If AB = 20, determine and state the length of arc MB. [Leave your answer in terms of π.]

Answer:
The circumference of a full circle is 2πr. For an arc, it is the circumference times the fraction of the circle, which is denoted by the measure of the circle arc divided by 360 degrees.

So 36/360 (2)(20)π = 4π.

That's all there was to this.

31. In triagnels ANT and ELM below, AN = 6, NT = 5.6, TA = 4, EL = 9, LM = 8.4, and ME = 6.

Explain why △ANT ~ △ELM

Answer: You can show that two triangles are similar by showing that all three pairs of corresponding sides are proportional by SSS. Also, one triangle is the image of the other after a dilation of a particular scale factor. ("Obviously", saying this is not enough. You need to provide the numbers.)

6/4 = 1.5, 9/6 = 1.5, and 8.4/5.6 = 1.5.

Triangle ELM is a dilation of ANT by a scale faction of 1.5. All of the corresponding sides are proportional so the two are similar by SSS.

Note: if SSS wasn't mentioned, you likely lost a point.

End of Part II

How did you do?

Questions, comments and corrections welcome.

I also write Fiction! The NEW COLLECTION IS AVIALABLE! A Bucket Full of Moonlight, written by Christopher J. Burke, contains 30+ pieces of short stories and flash fiction. It's available from eSpec Books! Order the softcover or ebook at Amazon. Vampires, werewolves, angels, demons, used-car salesmen, fairies, superheroes, space and time travel, and little gray aliens talking to rock creatures and living plants.
My other books include my Burke's Lore Briefs series and In A Flash 2020.
If you enjoy my books, please consider leaving a rating or review on Amazon or on Good Reads. Thank you!

Geometry Problems of the Day (Geometry Regents, January 2025 Part II)

This exam was adminstered in January 2025.

January 2025 Geometry, Part II

Each correct answer is worth up to 2 credits. Partial credit can be given. Work must be shown or explained.

25. In the diagram below, quadrilateral BCDE maps onto quadrilateral JKLM using a sequence of rigid motions.

Determine and state the degree measure of angle D.

Answer:

Angle B is congruent to Angle J. Angle C is congruent to Angle K. The sum of the four angles in a quadrilateral is 360 degrees.

70 + 117 + 91 = 278 and 360 - 278 = 82 degrees, so the measure of angle D is 82 degrees.

26. Given AB below, use a compass and a straightedge to construct a segment that is 1/4 AB. [Leave all construction marks.]

Answer:

Construct a perpendicular bisector to find the midpoint. Then find construct another perpendicular bisector between A and the midpoint. Half of a half is a quarter.

If you label the new point C, then AC = 1/4 AB.

The following illustration was provided by New York State.

27. A dog sees a bird in a tree. The angle of elevation from the dog’s eyes to the bird is 36°, as modeled below.

The dog is 18.5 feet away from the base of the tree, and his eyes are 2.5 feet above the ground.
Determine and state how high the bird is above the ground, to the nearest foot.

Answer:

In the right triangle shown, you have the base, which is adjacent to the angle, and you want to find the height, which is the opposite of the angle. This means that you want to use TAN to find the height. And then you have to add 2.5 feet because the triangle isn't on the ground.

tan 36 = x/18.5
x = 18.5 tan 36 = 13.44..

Add 13.4 + 2.5 = 15.9, which is 16 feet to the nearest foot.

28. Pure silver has a density of 10.5 g/cm³. Samantha has a pure silver charm on her necklace in the shape of a sphere. The radius of the charm is 0.5 cm.
Determine and state the mass of the charm, to the nearest tenth of a gram.

Answer:

You have the density. You need to find the Volume so you can find the mass, using the formula D = m/V.

V = 4/3 π r³ = 4/3 (0.5)³ = 0.523...

Use this Volume in the Density formula to find the Mass.

D = m/V
10.5 = m / 0.523
m = (10.5)(0.523) = 5.4915.

The mass is 5.5 grams.

29. In △ABC, below, DE is drawn such that AD = 4, DB = 8, AE = 3, and EC = 6.

Explain why △ADE ~ △ABC.

Answer:
You may recall that a midsegment connects the midpoints of two sides of a triangle and is parallel to the third side. The property of being parallel to the third side is true for any segment that connects two points that have the same proportionality as well.

3/6 = 1/2, so AE:EC = 1:2, and 4/8 = 1/2, so AD:DB = 1:2.

Since ED connects two points with the same proportionality, ED || CB. Since the lines are parallel then ∠C ≅ ∠AED and ∠D ≅ ∠ADE. (Also, ∠A is congruent to itself.) By AA, △ADE ~ △ABC.

30. In circle E below, tangent PA and secant PBC are drawn.

If PB =9 and BC = 16, determine and state the length of PA.

Answer:
The Tangent-Secant Theorem tells us that the square of the tangent is equal to the product of the length of the secant line times the portion of the line that is outside the circle. (If you think about it, you are also multiplying the length of the tangent by the portion that is outside the circle!)

(PA)² = (PB)(PC) = (9)(9 + 16) = (9)(25) = (225)
PA = &sqrt;(225) = 15

Note that the square root of 9 is 3 and the square root of 25 is 5, and that 3 * 5 = 15. That works as well.

31. In a right triangle, sin(4x + 3)° = cos(2x - 9)°. Determine and state the value of x.

Answer: If the sine of one angle is equalt to the cosine of another angle, then the sum of the two angles is 90 degrees. The "co" in "cosine" stands for "complementary", and complementary angles add up to 90 degrees.

4x + 3 + 2x - 9 = 90
6x - 6 = 90
6x = 96
x = 16

End of Part II

How did you do?

Questions, comments and corrections welcome.

I also write Fiction! The NEW COLLECTION IS AVIALABLE! A Bucket Full of Moonlight, written by Christopher J. Burke, contains 30+ pieces of short stories and flash fiction. It's available from eSpec Books! Order the softcover or ebook at Amazon. Vampires, werewolves, angels, demons, used-car salesmen, fairies, superheroes, space and time travel, and little gray aliens talking to rock creatures and living plants.
My other books include my Burke's Lore Briefs series and In A Flash 2020.
If you enjoy my books, please consider leaving a rating or review on Amazon or on Good Reads. Thank you!

Algebra 2 Problems of the Day (Algebra 2, January 2025 Part I)

This exam was adminstered in January 2025.

More Regents problems.

January 2025 Algebra 2 Regents

Part I

Each correct answer will receive 2 credits. No partial credit.


17. If 4(10^5x-2) = 12, then x equals

(1) 2.3/5
(2) 1/3( log12/log40 + 5)
(3) (log(3) + 2) / 5
(4) 1/5 (log12/log4 + 2)

Answer: (3) (log(3) + 2) / 5

The rules for logarithms are derived from the rules of exponents. Remember that if you have difficulty. Use inverse operations to find x.

4(10^5x-2) = 12
10^5x-2) = 3
log₁₀3 = 5x - 2
log(3) + 2 = 5x
(log(3) + 2) / 5 = x

This is Choice (3).

18. A random sample of 152 students was surveyed on a particular day about how they got to school. The survey results are summarized in the table below.

Which statement is best supported by the data?

(1) The probability of being late given that a student walked is greater than the probability that a student walked given that the student was late.
(2) The probability of being late given that a student walked is less than the probability that a student walked given that the student was late.
(3) The probability of being late given that a student walked is equal to the probability that a student walked given that the student was late.
(4) The probability of being late given that a student walked cannot be determined.

Answer: (1) The probability of being late given that a student walked is greater than the probability that a student walked given that the student was late.

Write in the subtotals and the grand total to make the calculations easier:

In Choice (1), the probability of being late given that a student walked is 4/22. The probability that a student walked given that the student was late is 4/30. The first probability is greater than the second, so this is the correct answer.

Choice (2) says the first should be less, but it is not. Choice (3) says that the two are equal, but they are not. Choice (4) says the probability cannot be determined, but it can be. (We just did it!)

The correct answer is Choice (1).

19. If f(x) = ³√(x) + 4, then f^-1(x) equals

(1) ³√(x - 4)
(2) (x - 4)³
(3) x³ + 1/4
(4) -³√(x) - 4

Answer: (2) (x - 4)³

Substitute the x with a y, then set the expression equal to x. Finally, rewrite the equation to solve for y.

x = ³√(y) + 4
x - 4 = ³√(y)
(x - 4)³ = y

The correct answer is Choice (1).

20. Given the equation S(x) = 1.7sin(bx) + 12, where the period of S(x) is 12, what is the value of b?

(1) π/6
(2) 24π
(3) π/12
(4) 6π

Answer: (1) π/6

The period of a sine function is 2π/b. We want to find b. The "+ 12" in the function is meaningless to this problem because it has nothing to do with the period, which is also 12.

2π/b = 12
2π/12 = b
π/6 = b

Choice (1) is the correct answer.

21. Jin solved the equation √(4 - x) = x + 8 by squaring both sides. What extraneous solution did he find?

(1) -5
(2) -12
(3) 3
(4) 4

Answer: (2) -12

The extraneous value would be one that wouldn't make a valid equation. For examples, if a "solution" makes the expression x + 8 into a negative number, then that solution is extraneous because the value of the square root cannot be negative. The only possible answer from the four choices is (2) -12.

If you wanted to solve it to check (or if there had been more possibilities):

√(4 - x) = x + 8
4 - x = (x + 8)²
4 - x = x² + 16x + 64
0 = x² + 17x + 60
0 = (x + 12)(x + 5)
x + 12 = 0 or x + 5 = 0
x = -12 or x = -5

The solution x = -5 is valid because √(4 - (-5) = (-5) + 8 is a true statement becasue 3 = 3.

However, √(4 - (-12)) = (-12) + 8 is not a true statement because 4 =/= -4.

The correct answer is Choice (2).

22.The expression (x² + y²)² is not equivalent to

(1) (x² - y²)² + (2xy)²
(2) (x + y)⁴ + 2(xy)²
(3) x²(x²+2y²) + (y²)²
(4) (2x² + y²)² - (3x⁴ + 2x²y²)

Answer: (2) (x + y)⁴ + 2(xy)²

If you want a calculator "shortcut", replace x with a value such as 5 and y with a value such as 7 (note that 5 and 7 are mutually prime) and calculate all five expressions to see which doesn't match.

On first look, my "educated guess" would be Choice (2), but let's check all of them:

(x² + y²)² = x⁴ + 2x²y² + y⁴

In Choice (1) (x² - y²)² + (2xy)²
= x⁴ - 2x²y² + y⁴ + (4xy)²
= x⁴ + 2x²y² + y⁴

In Choice (2), (x + y)⁴ is NOT equal to x⁴ + y⁴.
(x + y)⁴ + 2(xy)²
= x⁴ + 4x³y + 6x²y² + 4xy³ + y⁴ + 4x²y²
This is totally different from the original expression. Choice (2) is the correct answer.

In Choice (3) x²(x²+2y²) + (y²)²
= x⁴ + 2x²y² + y⁴

In Choice (4) (2x² + y²)² - (3x⁴ + 2x²y²)
= 4x⁴ + 4x²y² + y⁴ - 3x⁴ - 2x²y²
= x⁴ + 2x²y² + y⁴

23. The height of a running trail is modeled by the quartic function y = f(x) shown below, where x is the distance in miles from the start of the trail and y is the height in feet relative to sea level.
If this trail has a minimum height of 16 feet below sea level, which function(s) could represent a running trail whose minimum height is half of the minimum height of the original trail?

I. y = f(1/2 x); II. y = f(x) + 8; III. y = 1/2f(x)

(1) I, only
(2) II, only
(3) I and III
(4) II and III

Answer: (4) II and III

Half of the minimum height would be 8 feet below sea level instead of 16 feet. That mean that the minimum is either raised by 1/2 or raised by 8 feet.

In function I, putting 1/2 in front of x inside the parentheses, the function has changed the period but hasn't changed either the baseline or the amplitude. Function I is no good, so you can eliminate Choices (1) and (3).

Function II must be true because it's in both of the remaining choices. Adding 8 to the y value will raise the minimum from -16 to -8.

Function III shrinks the y value by 1/2, so -16 will become -8. Function III fits the description.

Choice (4) is the correct answer.

24. The crew aboard a small fishing boat caught 350 pounds of fish on Monday. From that Monday through the end of the week on Friday, the weight of the fish caught increased 15% per day. The total weight, in pounds, of fish caught is approximately

(1) 411
(2) 612
(3) 1748
(4) 2360

Answer: (4) 2360

Use the formula for the Geometric Series to find the sum:

S₅ = (350 - 350(1.15)⁵) / (1 - 1.15)

P = 2359.833...

The correct answer is Choice (4).

End of Part I. Comments and questions welcome.

I also write Fiction! The NEW COLLECTION IS AVIALABLE! A Bucket Full of Moonlight, written by Christopher J. Burke, contains 30+ pieces of short stories and flash fiction. It's available from eSpec Books! Order the softcover or ebook at Amazon. Vampires, werewolves, angels, demons, used-car salesmen, fairies, superheroes, space and time travel, and little gray aliens talking to rock creatures and living plants.
My other books include my Burke's Lore Briefs series and In A Flash 2020.
If you enjoy my books, please consider leaving a rating or review on Amazon or on Good Reads. Thank you!