Thursday, May 30, 2019

Algebra 2 Problems of the Day

Daily Algebra 2 questions and answers.
After a brief hiatus, the Algebra 2 Problems of the Day are back. Hopefully, daily.

More Algebra 2 problems.

January 2019, Part II

All Questions in Part I are worth 2 credits. Partial credit can be earned.


31. Point M (t, 4/7) is located in the second quadrant on the unit circle. Determine the exact value of t.

Answer:
Because point M is in Quadrant II, t must be negative.
Because point M is on the unit circle, t2 + (4/7)2 = 12

t2 + (4/7)2 = 1
t2 + 16/49 = 1
t2 = 33/49
t = + SQRT(33/49) = + SQRT(33)/7

You need to specify the exact value of t, so do NOT estimate or round the radical.
Also, it has to be negative so t = - SQRT(31)/7





32. On the grid below, graph the function y = log2(x - 3) + 1

Answer:
Put the equation in the calculator and look at the table of values.
The asymptote is x = 3.
Plot the values (4, 1), (5, 2), (7, 3), and (11, 4). And then draw the curve.





Comments and questions welcome.

More Algebra 2 problems.

No comments:

Post a Comment