Algebra 2 Problems of the Day

Daily Algebra 2 questions and answers.
After a brief hiatus, the Algebra 2 Problems of the Day are back. Hopefully, daily.

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January 2019, Part II

All Questions in Part I are worth 2 credits. Partial credit can be earned.


31. Point M (t, 4/7) is located in the second quadrant on the unit circle. Determine the exact value of t.

Answer:
Because point M is in Quadrant II, t must be negative.
Because point M is on the unit circle, t² + (4/7)² = 1²

t² + (4/7)² = 1
t² + 16/49 = 1
t² = 33/49
t = + SQRT(33/49) = + SQRT(33)/7
You need to specify the exact value of t, so do NOT estimate or round the radical.
Also, it has to be negative so t = - SQRT(31)/7

32. On the grid below, graph the function y = log₂(x - 3) + 1

Answer:
Put the equation in the calculator and look at the table of values.
The asymptote is x = 3.
Plot the values (4, 1), (5, 2), (7, 3), and (11, 4). And then draw the curve.

Comments and questions welcome.

More Algebra 2 problems.